What are the solutions to the equation c^2-16c+64=0 ?

The solutions to the equation c^2-16c+64=0 are c=8

Find the zeros of c^2-16c+64=0

The zeros of c^2-16c+64=0 are c=8

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c^{2} - 16 c + 64 = 0

c = 8

Solution steps

c^{2} - 16 c + 64 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 64}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 64 = 0

c_{1, 2} = \frac{- ( - 16 ) \pm 0}{2 \cdot 1}

c = \frac{- ( - 16 )}{2 \cdot 1}

\frac{- ( - 16 )}{2 \cdot 1} = 8

c = 8

The solution to the quadratic equation is:

c = 8

2 x^{2} + 16 x - 70 = - 4

x^{2} - 10 x + 25 = 36

3 n^{2} + 24 n = - 48

4 x^{2} + 4 (k - 2) x + k = 0

x^{2} + x = x + 3

What are the solutions to the equation c^2-16c+64=0 ?
The solutions to the equation c^2-16c+64=0 are c=8
Find the zeros of c^2-16c+64=0
The zeros of c^2-16c+64=0 are c=8