What are the solutions to the equation 8r^2+4r+5=0 ?

The solutions to the equation 8r^2+4r+5=0 are r=-1/4+i 3/4 ,r=-1/4-i 3/4

Find the zeros of 8r^2+4r+5=0

The zeros of 8r^2+4r+5=0 are r=-1/4+i 3/4 ,r=-1/4-i 3/4

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8 r^{2} + 4 r + 5 = 0

r = - \frac{1}{4} + i \frac{3}{4}, r = - \frac{1}{4} - i \frac{3}{4}

Solution steps

8 r^{2} + 4 r + 5 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 8 \cdot 5}{2 \cdot 8}

Simplify

4^{2} - 4 \cdot 8 \cdot 5 : 12 i

r_{1, 2} = \frac{- 4 \pm 12 i}{2 \cdot 8}

Separate the solutions

r_{1} = \frac{- 4 + 12 i}{2 \cdot 8}, r_{2} = \frac{- 4 - 12 i}{2 \cdot 8}

r = \frac{- 4 + 12 i}{2 \cdot 8} : - \frac{1}{4} + i \frac{3}{4}

r = \frac{- 4 - 12 i}{2 \cdot 8} : - \frac{1}{4} - i \frac{3}{4}

The solutions to the quadratic equation are:

r = - \frac{1}{4} + i \frac{3}{4}, r = - \frac{1}{4} - i \frac{3}{4}

(7 - 2 x) x = 6

y^{2} - 7 y - 3 = 0

x^{2} + 8 = 80

15 x - 10 = 6 x (x + 2) + (- x + 3)

n^{2} = 3 n + 40

What are the solutions to the equation 8r^2+4r+5=0 ?
The solutions to the equation 8r^2+4r+5=0 are r=-1/4+i 3/4 ,r=-1/4-i 3/4
Find the zeros of 8r^2+4r+5=0
The zeros of 8r^2+4r+5=0 are r=-1/4+i 3/4 ,r=-1/4-i 3/4