What are the solutions to the equation x^2+ax+a+8=0 ?

The solutions to the equation x^2+ax+a+8=0 are x=(-a+sqrt(a^2-4(a+8)))/2 ,x=(-a-sqrt(a^2-4(a+8)))/2

Find the zeros of x^2+ax+a+8=0

The zeros of x^2+ax+a+8=0 are x=(-a+sqrt(a^2-4(a+8)))/2 ,x=(-a-sqrt(a^2-4(a+8)))/2

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x^{2} + a x + a + 8 = 0

x = \frac{- a + a ^{2} - 4 ( a + 8 )}{2}, x = \frac{- a - a ^{2} - 4 ( a + 8 )}{2}

Solution steps

x^{2} + a x + a + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- a \pm a ^{2} - 4 \cdot 1 \cdot ( a + 8 )}{2 \cdot 1}

Simplify

a^{2} - 4 \cdot 1 \cdot (a + 8) : a^{2} - 4 (a + 8)

x_{1, 2} = \frac{- a \pm a ^{2} - 4 ( a + 8 )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- a + a ^{2} - 4 ( a + 8 )}{2 \cdot 1}, x_{2} = \frac{- a - a ^{2} - 4 ( a + 8 )}{2 \cdot 1}

x = \frac{- a + a ^{2} - 4 ( a + 8 )}{2 \cdot 1} : \frac{- a + a ^{2} - 4 ( a + 8 )}{2}

x = \frac{- a - a ^{2} - 4 ( a + 8 )}{2 \cdot 1} : \frac{- a - a ^{2} - 4 ( a + 8 )}{2}

The solutions to the quadratic equation are:

x = \frac{- a + a ^{2} - 4 ( a + 8 )}{2}, x = \frac{- a - a ^{2} - 4 ( a + 8 )}{2}

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1.75 \cdot 1 0^{- 2} = π (\frac{d}{2})^{2} \cdot 2.42

3 x^{2} + 7 x = 1

x^{2} + 12 x + 35 = 0

What are the solutions to the equation x^2+ax+a+8=0 ?
The solutions to the equation x^2+ax+a+8=0 are x=(-a+sqrt(a^2-4(a+8)))/2 ,x=(-a-sqrt(a^2-4(a+8)))/2
Find the zeros of x^2+ax+a+8=0
The zeros of x^2+ax+a+8=0 are x=(-a+sqrt(a^2-4(a+8)))/2 ,x=(-a-sqrt(a^2-4(a+8)))/2