What are the solutions to the equation solvefor x,3x^2-12x+9=0 ?

The solutions to the equation solvefor x,3x^2-12x+9=0 are x=3,x=1

Find the zeros of solvefor x,3x^2-12x+9=0

The zeros of solvefor x,3x^2-12x+9=0 are x=3,x=1

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x, 3 x^{2} - 12 x + 9 = 0

x = 3, x = 1

Solution steps

3 x^{2} - 12 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 \cdot 9}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 \cdot 9 = 6

x_{1, 2} = \frac{- ( - 12 ) \pm 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 6}{2 \cdot 3}

x = \frac{- ( - 12 ) + 6}{2 \cdot 3} : 3

x = \frac{- ( - 12 ) - 6}{2 \cdot 3} : 1

The solutions to the quadratic equation are:

x = 3, x = 1

4 x^{2} + 4 x - 6 = 0

x^{2} = - 7 x - 8

x^{2} - 2 x - 31 = 0

c, x^{2} + y^{2} - c^{2} = 0

x^{2} + 4 x - 221 = 0

What are the solutions to the equation solvefor x,3x^2-12x+9=0 ?
The solutions to the equation solvefor x,3x^2-12x+9=0 are x=3,x=1
Find the zeros of solvefor x,3x^2-12x+9=0
The zeros of solvefor x,3x^2-12x+9=0 are x=3,x=1