What are the solutions to the equation -x^2+5x=6 ?

The solutions to the equation -x^2+5x=6 are x=2,x=3

Find the zeros of -x^2+5x=6

The zeros of -x^2+5x=6 are x=2,x=3

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- x^{2} + 5 x = 6

x = 2, x = 3

Solution steps

- x^{2} + 5 x = 6

Move

6

to the left side

- x^{2} + 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) ( - 6 )}{2 ( - 1 )}

5^{2} - 4 (- 1) (- 6) = 1

x_{1, 2} = \frac{- 5 \pm 1}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5 + 1}{2 ( - 1 )}, x_{2} = \frac{- 5 - 1}{2 ( - 1 )}

x = \frac{- 5 + 1}{2 ( - 1 )} : 2

x = \frac{- 5 - 1}{2 ( - 1 )} : 3

The solutions to the quadratic equation are:

x = 2, x = 3

9 x^{2} - 36 x + 40 = 0

4 x^{2} - 32 x + 73 = 0

t, x = v t + \frac{1}{2} a t^{2}

100 x^{2} + 49 = 0

x, f = - 4 (x + h)^{2} - k

What are the solutions to the equation -x^2+5x=6 ?
The solutions to the equation -x^2+5x=6 are x=2,x=3
Find the zeros of -x^2+5x=6
The zeros of -x^2+5x=6 are x=2,x=3