What are the solutions to the equation 3(x-2)^2+225=0 ?

The solutions to the equation 3(x-2)^2+225=0 are x=5sqrt(3)i+2,x=-5sqrt(3)i+2

Find the zeros of 3(x-2)^2+225=0

The zeros of 3(x-2)^2+225=0 are x=5sqrt(3)i+2,x=-5sqrt(3)i+2

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3 (x - 2)^{2} + 225 = 0

x = 53 i + 2, x = - 53 i + 2

Solution steps

3 (x - 2)^{2} + 225 = 0

Move

225

to the right side

3 (x - 2)^{2} = - 225

Divide both sides by

3

(x - 2)^{2} = - 75

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = - 75 : x = 53 i + 2

Solve

x - 2 = - - 75 : x = - 53 i + 2

The solutions to the quadratic equation are:

x = 53 i + 2, x = - 53 i + 2

3 x^{2} + 33 x + 72 = 0

(x + 3) (x - 1) = (2 x + 3) (x + 5)

x^{2} + 8 x - 17 = 0

x^{2} + 9 x + 14 = 0

x^{2} + 8 x - 18 = 0

What are the solutions to the equation 3(x-2)^2+225=0 ?
The solutions to the equation 3(x-2)^2+225=0 are x=5sqrt(3)i+2,x=-5sqrt(3)i+2
Find the zeros of 3(x-2)^2+225=0
The zeros of 3(x-2)^2+225=0 are x=5sqrt(3)i+2,x=-5sqrt(3)i+2