What are the solutions to the equation 5x^2+20x+15=0 ?

The solutions to the equation 5x^2+20x+15=0 are x=-1,x=-3

Find the zeros of 5x^2+20x+15=0

The zeros of 5x^2+20x+15=0 are x=-1,x=-3

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5 x^{2} + 20 x + 15 = 0

x = - 1, x = - 3

Solution steps

5 x^{2} + 20 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 5 \cdot 15}{2 \cdot 5}

2 0^{2} - 4 \cdot 5 \cdot 15 = 10

x_{1, 2} = \frac{- 20 \pm 10}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 20 + 10}{2 \cdot 5}, x_{2} = \frac{- 20 - 10}{2 \cdot 5}

x = \frac{- 20 + 10}{2 \cdot 5} : - 1

x = \frac{- 20 - 10}{2 \cdot 5} : - 3

The solutions to the quadratic equation are:

x = - 1, x = - 3

3 (x - 2)^{2} + 3 = 6 x - 12

3 x^{2} - 6 x + 2 = 0

x^{2} - 11 x - 80 = 0

f, y = (f)^{2}

2 x^{2} + 12 x + 5 = 0

What are the solutions to the equation 5x^2+20x+15=0 ?
The solutions to the equation 5x^2+20x+15=0 are x=-1,x=-3
Find the zeros of 5x^2+20x+15=0
The zeros of 5x^2+20x+15=0 are x=-1,x=-3