What are the solutions to the equation 2x^2+12x+8=0 ?

The solutions to the equation 2x^2+12x+8=0 are x=-3+sqrt(5),x=-3-sqrt(5)

Find the zeros of 2x^2+12x+8=0

The zeros of 2x^2+12x+8=0 are x=-3+sqrt(5),x=-3-sqrt(5)

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2 x^{2} + 12 x + 8 = 0

x = - 3 + 5, x = - 3 - 5

Decimal Notation

x = - 0.76393 \dots, x = - 5.23606 \dots

Solution steps

2 x^{2} + 12 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

1 2^{2} - 4 \cdot 2 \cdot 8 = 45

x_{1, 2} = \frac{- 12 \pm 4 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 12 + 4 5}{2 \cdot 2}, x_{2} = \frac{- 12 - 4 5}{2 \cdot 2}

x = \frac{- 12 + 4 5}{2 \cdot 2} : - 3 + 5

x = \frac{- 12 - 4 5}{2 \cdot 2} : - 3 - 5

The solutions to the quadratic equation are:

x = - 3 + 5, x = - 3 - 5

8 x - x^{2} = 12

5 x^{2} + 35 x - 90 = 0

15 x + 15 = - 4 x^{2}

4 x^{2} + 12 x + 9 = 0

x^{2} - 4 x + 2 = 0

What are the solutions to the equation 2x^2+12x+8=0 ?
The solutions to the equation 2x^2+12x+8=0 are x=-3+sqrt(5),x=-3-sqrt(5)
Find the zeros of 2x^2+12x+8=0
The zeros of 2x^2+12x+8=0 are x=-3+sqrt(5),x=-3-sqrt(5)