What are the solutions to the equation 4x^2+4=-7x ?

The solutions to the equation 4x^2+4=-7x are x=-7/8+i(sqrt(15))/8 ,x=-7/8-i(sqrt(15))/8

Find the zeros of 4x^2+4=-7x

The zeros of 4x^2+4=-7x are x=-7/8+i(sqrt(15))/8 ,x=-7/8-i(sqrt(15))/8

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4 x^{2} + 4 = - 7 x

x = - \frac{7}{8} + i \frac{15}{8}, x = - \frac{7}{8} - i \frac{15}{8}

Solution steps

4 x^{2} + 4 = - 7 x

Move

7 x

to the left side

4 x^{2} + 4 + 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 7 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 4 \cdot 4}{2 \cdot 4}

Simplify

7^{2} - 4 \cdot 4 \cdot 4 : 15 i

x_{1, 2} = \frac{- 7 \pm 15 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 7 + 15 i}{2 \cdot 4}, x_{2} = \frac{- 7 - 15 i}{2 \cdot 4}

x = \frac{- 7 + 15 i}{2 \cdot 4} : - \frac{7}{8} + i \frac{15}{8}

x = \frac{- 7 - 15 i}{2 \cdot 4} : - \frac{7}{8} - i \frac{15}{8}

The solutions to the quadratic equation are:

x = - \frac{7}{8} + i \frac{15}{8}, x = - \frac{7}{8} - i \frac{15}{8}

2 X^{2} + 4 X - 6 = 0

8 x^{2} = - 4 x

x, x^{2} + y^{2} - 4 x + 2 y + 14 = 0

x, (x + 1)^{2} + (y - 3)^{2} = 0

2 x^{2} + 13 x + 20

What are the solutions to the equation 4x^2+4=-7x ?
The solutions to the equation 4x^2+4=-7x are x=-7/8+i(sqrt(15))/8 ,x=-7/8-i(sqrt(15))/8
Find the zeros of 4x^2+4=-7x
The zeros of 4x^2+4=-7x are x=-7/8+i(sqrt(15))/8 ,x=-7/8-i(sqrt(15))/8