What are the solutions to the equation 3x^2-24x+48=-363 ?

The solutions to the equation 3x^2-24x+48=-363 are x=4+11i,x=4-11i

Find the zeros of 3x^2-24x+48=-363

The zeros of 3x^2-24x+48=-363 are x=4+11i,x=4-11i

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3 x^{2} - 24 x + 48 = - 363

x = 4 + 11 i, x = 4 - 11 i

Solution steps

3 x^{2} - 24 x + 48 = - 363

Move

363

to the left side

3 x^{2} - 24 x + 411 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 3 \cdot 411}{2 \cdot 3}

Simplify

(- 24)^{2} - 4 \cdot 3 \cdot 411 : 66 i

x_{1, 2} = \frac{- ( - 24 ) \pm 66 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 66 i}{2 \cdot 3}, x_{2} = \frac{- ( - 24 ) - 66 i}{2 \cdot 3}

x = \frac{- ( - 24 ) + 66 i}{2 \cdot 3} : 4 + 11 i

x = \frac{- ( - 24 ) - 66 i}{2 \cdot 3} : 4 - 11 i

The solutions to the quadratic equation are:

x = 4 + 11 i, x = 4 - 11 i

5 x^{2} + 21 x = - 4

(x - 5)^{2} = 20

12 x^{2} + 5 x - 3 = 0

x, (x - 2)^{2} + (y - 3)^{2} = - 1

4 + 5 z - 6 z^{2} = 0

What are the solutions to the equation 3x^2-24x+48=-363 ?
The solutions to the equation 3x^2-24x+48=-363 are x=4+11i,x=4-11i
Find the zeros of 3x^2-24x+48=-363
The zeros of 3x^2-24x+48=-363 are x=4+11i,x=4-11i