What are the solutions to the equation -s^2+2s-8=0 ?

The solutions to the equation -s^2+2s-8=0 are s=1-sqrt(7)i,s=1+sqrt(7)i

Find the zeros of -s^2+2s-8=0

The zeros of -s^2+2s-8=0 are s=1-sqrt(7)i,s=1+sqrt(7)i

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- s^{2} + 2 s - 8 = 0

s = 1 - 7 i, s = 1 + 7 i

Solution steps

- s^{2} + 2 s - 8 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) ( - 8 )}{2 ( - 1 )}

Simplify

2^{2} - 4 (- 1) (- 8) : 27 i

s_{1, 2} = \frac{- 2 \pm 2 7 i}{2 ( - 1 )}

Separate the solutions

s_{1} = \frac{- 2 + 2 7 i}{2 ( - 1 )}, s_{2} = \frac{- 2 - 2 7 i}{2 ( - 1 )}

s = \frac{- 2 + 2 7 i}{2 ( - 1 )} : 1 - 7 i

s = \frac{- 2 - 2 7 i}{2 ( - 1 )} : 1 + 7 i

The solutions to the quadratic equation are:

s = 1 - 7 i, s = 1 + 7 i

- 6 x^{2} - 5 x + 1 = 0

12 x^{2} + 12 x - 24 = 0

3 (5 x + 7)^{2} - 31 = - 4

x^{2} + 53 = 16 x

3 y^{2} - 6 y = 8

What are the solutions to the equation -s^2+2s-8=0 ?
The solutions to the equation -s^2+2s-8=0 are s=1-sqrt(7)i,s=1+sqrt(7)i
Find the zeros of -s^2+2s-8=0
The zeros of -s^2+2s-8=0 are s=1-sqrt(7)i,s=1+sqrt(7)i