What are the solutions to the equation -16x^2+64x+48=0 ?

The solutions to the equation -16x^2+64x+48=0 are x=2-sqrt(7),x=2+sqrt(7)

Find the zeros of -16x^2+64x+48=0

The zeros of -16x^2+64x+48=0 are x=2-sqrt(7),x=2+sqrt(7)

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- 16 x^{2} + 64 x + 48 = 0

x = 2 - 7, x = 2 + 7

Decimal Notation

x = - 0.64575 \dots, x = 4.64575 \dots

Solution steps

- 16 x^{2} + 64 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 64 \pm 6 4 ^{2} - 4 ( - 16 ) \cdot 48}{2 ( - 16 )}

6 4^{2} - 4 (- 16) \cdot 48 = 327

x_{1, 2} = \frac{- 64 \pm 32 7}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 64 + 32 7}{2 ( - 16 )}, x_{2} = \frac{- 64 - 32 7}{2 ( - 16 )}

x = \frac{- 64 + 32 7}{2 ( - 16 )} : 2 - 7

x = \frac{- 64 - 32 7}{2 ( - 16 )} : 2 + 7

The solutions to the quadratic equation are:

x = 2 - 7, x = 2 + 7

y, y^{2} = x^{2} (x + 5)

x^{2} - 3 x = 30

3 x^{2} + 48 x + 183 = 0

x^{2} - 2 x - 3 = 0

2 x^{2} + 5 x + 3 = 0

What are the solutions to the equation -16x^2+64x+48=0 ?
The solutions to the equation -16x^2+64x+48=0 are x=2-sqrt(7),x=2+sqrt(7)
Find the zeros of -16x^2+64x+48=0
The zeros of -16x^2+64x+48=0 are x=2-sqrt(7),x=2+sqrt(7)