What are the solutions to the equation 5x^2+80x=-270 ?

The solutions to the equation 5x^2+80x=-270 are x=-8+sqrt(10),x=-8-sqrt(10)

Find the zeros of 5x^2+80x=-270

The zeros of 5x^2+80x=-270 are x=-8+sqrt(10),x=-8-sqrt(10)

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5 x^{2} + 80 x = - 270

x = - 8 + 10, x = - 8 - 10

Decimal Notation

x = - 4.83772 \dots, x = - 11.16227 \dots

Solution steps

5 x^{2} + 80 x = - 270

Move

270

to the left side

5 x^{2} + 80 x + 270 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 \cdot 5 \cdot 270}{2 \cdot 5}

8 0^{2} - 4 \cdot 5 \cdot 270 = 1010

x_{1, 2} = \frac{- 80 \pm 10 10}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 80 + 10 10}{2 \cdot 5}, x_{2} = \frac{- 80 - 10 10}{2 \cdot 5}

x = \frac{- 80 + 10 10}{2 \cdot 5} : - 8 + 10

x = \frac{- 80 - 10 10}{2 \cdot 5} : - 8 - 10

The solutions to the quadratic equation are:

x = - 8 + 10, x = - 8 - 10

5 x^{2} - 10 x - 8 = 0

y, 2 x^{2} y + \frac{( x ^{3} - y ^{2} )}{x} + 3 = 0

- x^{2} + 3 x + 1 = 0

x^{2} - 10 x + 24

x^{2} + 1.3 x = 0

What are the solutions to the equation 5x^2+80x=-270 ?
The solutions to the equation 5x^2+80x=-270 are x=-8+sqrt(10),x=-8-sqrt(10)
Find the zeros of 5x^2+80x=-270
The zeros of 5x^2+80x=-270 are x=-8+sqrt(10),x=-8-sqrt(10)