What are the solutions to the equation 5x^2+23x+12=0 ?

The solutions to the equation 5x^2+23x+12=0 are x=-3/5 ,x=-4

Find the zeros of 5x^2+23x+12=0

The zeros of 5x^2+23x+12=0 are x=-3/5 ,x=-4

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5 x^{2} + 23 x + 12 = 0

x = - \frac{3}{5}, x = - 4

Decimal Notation

x = - 0.6, x = - 4

Solution steps

5 x^{2} + 23 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 \cdot 5 \cdot 12}{2 \cdot 5}

2 3^{2} - 4 \cdot 5 \cdot 12 = 17

x_{1, 2} = \frac{- 23 \pm 17}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 23 + 17}{2 \cdot 5}, x_{2} = \frac{- 23 - 17}{2 \cdot 5}

x = \frac{- 23 + 17}{2 \cdot 5} : - \frac{3}{5}

x = \frac{- 23 - 17}{2 \cdot 5} : - 4

The solutions to the quadratic equation are:

x = - \frac{3}{5}, x = - 4

12 x^{2} - 75 = 0

x^{2} + 4 x + 3 = 0

25 x^{2} + 2 (x - 4)^{2} = - 3

x, x^{2} + 5 x y - 2 y = 12

16 x^{2} = 2 x

What are the solutions to the equation 5x^2+23x+12=0 ?
The solutions to the equation 5x^2+23x+12=0 are x=-3/5 ,x=-4
Find the zeros of 5x^2+23x+12=0
The zeros of 5x^2+23x+12=0 are x=-3/5 ,x=-4