What are the solutions to the equation 0.2w^2-0.3w=20 ?

The solutions to the equation 0.2w^2-0.3w=20 are w=(3+sqrt(1609))/4 ,w=(3-sqrt(1609))/4

Find the zeros of 0.2w^2-0.3w=20

The zeros of 0.2w^2-0.3w=20 are w=(3+sqrt(1609))/4 ,w=(3-sqrt(1609))/4

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0.2 w^{2} - 0.3 w = 20

w = \frac{3 + 1609}{4}, w = \frac{3 - 1609}{4}

Decimal Notation

w = 10.77808 \dots, w = - 9.27808 \dots

Solution steps

0.2 w^{2} - 0.3 w = 20

Multiply both sides by

10

2 w^{2} - 3 w = 200

Move

200

to the left side

2 w^{2} - 3 w - 200 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 200 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 200) = 1609

w_{1, 2} = \frac{- ( - 3 ) \pm 1609}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- ( - 3 ) + 1609}{2 \cdot 2}, w_{2} = \frac{- ( - 3 ) - 1609}{2 \cdot 2}

w = \frac{- ( - 3 ) + 1609}{2 \cdot 2} : \frac{3 + 1609}{4}

w = \frac{- ( - 3 ) - 1609}{2 \cdot 2} : \frac{3 - 1609}{4}

The solutions to the quadratic equation are:

w = \frac{3 + 1609}{4}, w = \frac{3 - 1609}{4}

x^{2} - x + \frac{5}{4} = 0

x (x - 16) - 20 = - 3

4^{2} + b^{2} = 8^{2}

r, y = π r^{2}

(x - 3)^{2} + (x + 1)^{2} = 12

What are the solutions to the equation 0.2w^2-0.3w=20 ?
The solutions to the equation 0.2w^2-0.3w=20 are w=(3+sqrt(1609))/4 ,w=(3-sqrt(1609))/4
Find the zeros of 0.2w^2-0.3w=20
The zeros of 0.2w^2-0.3w=20 are w=(3+sqrt(1609))/4 ,w=(3-sqrt(1609))/4