What are the solutions to the equation x^2-18x-4.95=0 ?

The solutions to the equation x^2-18x-4.95=0 are x=(3(30+sqrt(955)))/(10),x=(3(30-sqrt(955)))/(10)

Find the zeros of x^2-18x-4.95=0

The zeros of x^2-18x-4.95=0 are x=(3(30+sqrt(955)))/(10),x=(3(30-sqrt(955)))/(10)

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x^{2} - 18 x - 4.95 = 0

x = \frac{3 ( 30 + 955 )}{10}, x = \frac{3 ( 30 - 955 )}{10}

Decimal Notation

x = 18.27092 \dots, x = - 0.27092 \dots

Solution steps

x^{2} - 18 x - 4.95 = 0

Multiply both sides by

100

100 x^{2} - 1800 x - 495 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1800 ) \pm ( - 1800 ) ^{2} - 4 \cdot 100 ( - 495 )}{2 \cdot 100}

(- 1800)^{2} - 4 \cdot 100 (- 495) = 60955

x_{1, 2} = \frac{- ( - 1800 ) \pm 60 955}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- ( - 1800 ) + 60 955}{2 \cdot 100}, x_{2} = \frac{- ( - 1800 ) - 60 955}{2 \cdot 100}

x = \frac{- ( - 1800 ) + 60 955}{2 \cdot 100} : \frac{3 ( 30 + 955 )}{10}

x = \frac{- ( - 1800 ) - 60 955}{2 \cdot 100} : \frac{3 ( 30 - 955 )}{10}

The solutions to the quadratic equation are:

x = \frac{3 ( 30 + 955 )}{10}, x = \frac{3 ( 30 - 955 )}{10}

x, x^{2} - x y + y^{2} = 0

x^{2} - 4 x = - 10

64 x^{2} + 10 = 19

6 x^{2} + 11 x - 7 = 0

- 5 k^{2} + 7 k + 31 = 7

What are the solutions to the equation x^2-18x-4.95=0 ?
The solutions to the equation x^2-18x-4.95=0 are x=(3(30+sqrt(955)))/(10),x=(3(30-sqrt(955)))/(10)
Find the zeros of x^2-18x-4.95=0
The zeros of x^2-18x-4.95=0 are x=(3(30+sqrt(955)))/(10),x=(3(30-sqrt(955)))/(10)