What are the solutions to the equation -5k^2+7k+31=7 ?

The solutions to the equation -5k^2+7k+31=7 are k=-8/5 ,k=3

Find the zeros of -5k^2+7k+31=7

The zeros of -5k^2+7k+31=7 are k=-8/5 ,k=3

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- 5 k^{2} + 7 k + 31 = 7

k = - \frac{8}{5}, k = 3

Decimal Notation

k = - 1.6, k = 3

Solution steps

- 5 k^{2} + 7 k + 31 = 7

Move

7

to the left side

- 5 k^{2} + 7 k + 24 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 5 ) \cdot 24}{2 ( - 5 )}

7^{2} - 4 (- 5) \cdot 24 = 23

k_{1, 2} = \frac{- 7 \pm 23}{2 ( - 5 )}

Separate the solutions

k_{1} = \frac{- 7 + 23}{2 ( - 5 )}, k_{2} = \frac{- 7 - 23}{2 ( - 5 )}

k = \frac{- 7 + 23}{2 ( - 5 )} : - \frac{8}{5}

k = \frac{- 7 - 23}{2 ( - 5 )} : 3

The solutions to the quadratic equation are:

k = - \frac{8}{5}, k = 3

7 p^{2} + 16 = 2151

2 x^{2} - 5 x + 20 = 0

4 x - 3 x^{2} = 0

x^{2} + 2 x - 4 = 3 x - 8

9^{2} + 4 0^{2} = c^{2}

What are the solutions to the equation -5k^2+7k+31=7 ?
The solutions to the equation -5k^2+7k+31=7 are k=-8/5 ,k=3
Find the zeros of -5k^2+7k+31=7
The zeros of -5k^2+7k+31=7 are k=-8/5 ,k=3