What are the solutions to the equation 7p^2+16=2151 ?

The solutions to the equation 7p^2+16=2151 are p=sqrt(305),p=-sqrt(305)

Find the zeros of 7p^2+16=2151

The zeros of 7p^2+16=2151 are p=sqrt(305),p=-sqrt(305)

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7 p^{2} + 16 = 2151

p = 305, p = - 305

Decimal Notation

p = 17.46424 \dots, p = - 17.46424 \dots

Solution steps

7 p^{2} + 16 = 2151

Move

16

to the right side

7 p^{2} = 2135

Divide both sides by

7

p^{2} = 305

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = 305, p = - 305

2 x^{2} - 5 x + 20 = 0

4 x - 3 x^{2} = 0

x^{2} + 2 x - 4 = 3 x - 8

9^{2} + 4 0^{2} = c^{2}

4 x^{2} - 9 = 7

What are the solutions to the equation 7p^2+16=2151 ?
The solutions to the equation 7p^2+16=2151 are p=sqrt(305),p=-sqrt(305)
Find the zeros of 7p^2+16=2151
The zeros of 7p^2+16=2151 are p=sqrt(305),p=-sqrt(305)