What are the solutions to the equation 9^2+40^2=c^2 ?

The solutions to the equation 9^2+40^2=c^2 are c=41,c=-41

Find the zeros of 9^2+40^2=c^2

The zeros of 9^2+40^2=c^2 are c=41,c=-41

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9^{2} + 4 0^{2} = c^{2}

c = 41, c = - 41

Solution steps

9^{2} + 4 0^{2} = c^{2}

Switch sides

c^{2} = 9^{2} + 4 0^{2}

Simplify

9^{2} + 4 0^{2} : 1681

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 1681, c = - 1681

1681 = 41

- 1681 = - 41

c = 41, c = - 41

4 x^{2} - 9 = 7

- 4 x^{2} + 64 x + 256 = 0

x^{2} - 17 x + 52 = 0

- \frac{1}{2} x^{2} - x + \frac{3}{2} = 0

2 x^{2} + 11 x + 15

What are the solutions to the equation 9^2+40^2=c^2 ?
The solutions to the equation 9^2+40^2=c^2 are c=41,c=-41
Find the zeros of 9^2+40^2=c^2
The zeros of 9^2+40^2=c^2 are c=41,c=-41