What are the solutions to the equation completesquare-4x^2+64x+256=0 ?

The solutions to the equation completesquare-4x^2+64x+256=0 are x=8sqrt(2)+8,x=-8sqrt(2)+8

Find the zeros of completesquare-4x^2+64x+256=0

The zeros of completesquare-4x^2+64x+256=0 are x=8sqrt(2)+8,x=-8sqrt(2)+8

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- 4 x^{2} + 64 x + 256 = 0

x = 82 + 8, x = - 82 + 8

Decimal Notation

x = 19.31370 \dots, x = - 3.31370 \dots

Solution steps

- 4 x^{2} + 64 x + 256 = 0

Move

256

to the right side

- 4 x^{2} + 64 x = - 256

Divide both sides by

- 4

\frac{- 4 x ^{2} + 64 x}{- 4} = \frac{- 256}{- 4}

x^{2} - 16 x = 64

Rewrite in the form

(x + a)^{2} = b

(x - 8)^{2} = 128

For

the solutions are

f (x) = a, - a

Solve

x - 8 = 128 : x = 82 + 8

Solve

x - 8 = - 128 : x = - 82 + 8

The solutions to the quadratic equation are:

x = 82 + 8, x = - 82 + 8

x^{2} - 17 x + 52 = 0

- \frac{1}{2} x^{2} - x + \frac{3}{2} = 0

2 x^{2} + 11 x + 15

2 x^{2} + 12 x - 13 = 0

x (2 x + 3) = 5

What are the solutions to the equation completesquare-4x^2+64x+256=0 ?
The solutions to the equation completesquare-4x^2+64x+256=0 are x=8sqrt(2)+8,x=-8sqrt(2)+8
Find the zeros of completesquare-4x^2+64x+256=0
The zeros of completesquare-4x^2+64x+256=0 are x=8sqrt(2)+8,x=-8sqrt(2)+8