What are the solutions to the equation -1/2 x^2-x+3/2 =0 ?

The solutions to the equation -1/2 x^2-x+3/2 =0 are x=-3,x=1

Find the zeros of -1/2 x^2-x+3/2 =0

The zeros of -1/2 x^2-x+3/2 =0 are x=-3,x=1

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- \frac{1}{2} x^{2} - x + \frac{3}{2} = 0

x = - 3, x = 1

Solution steps

- \frac{1}{2} x^{2} - x + \frac{3}{2} = 0

Multiply both sides by

2

- x^{2} - 2 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) \cdot 3}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) \cdot 3 = 4

x_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4}{2 ( - 1 )}, x_{2} = \frac{- ( - 2 ) - 4}{2 ( - 1 )}

x = \frac{- ( - 2 ) + 4}{2 ( - 1 )} : - 3

x = \frac{- ( - 2 ) - 4}{2 ( - 1 )} : 1

The solutions to the quadratic equation are:

x = - 3, x = 1

2 x^{2} + 11 x + 15

2 x^{2} + 12 x - 13 = 0

x (2 x + 3) = 5

k^{2} = 49

- 1 = x^{2} - 2 x

What are the solutions to the equation -1/2 x^2-x+3/2 =0 ?
The solutions to the equation -1/2 x^2-x+3/2 =0 are x=-3,x=1
Find the zeros of -1/2 x^2-x+3/2 =0
The zeros of -1/2 x^2-x+3/2 =0 are x=-3,x=1