What are the solutions to the equation 32x^2=17-18x ?

The solutions to the equation 32x^2=17-18x are x= 1/2 ,x=-17/16

Find the zeros of 32x^2=17-18x

The zeros of 32x^2=17-18x are x= 1/2 ,x=-17/16

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32 x^{2} = 17 - 18 x

x = \frac{1}{2}, x = - \frac{17}{16}

Decimal Notation

x = 0.5, x = - 1.0625

Solution steps

32 x^{2} = 17 - 18 x

Move

18 x

to the left side

32 x^{2} + 18 x = 17

Move

17

to the left side

32 x^{2} + 18 x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 32 ( - 17 )}{2 \cdot 32}

1 8^{2} - 4 \cdot 32 (- 17) = 50

x_{1, 2} = \frac{- 18 \pm 50}{2 \cdot 32}

Separate the solutions

x_{1} = \frac{- 18 + 50}{2 \cdot 32}, x_{2} = \frac{- 18 - 50}{2 \cdot 32}

x = \frac{- 18 + 50}{2 \cdot 32} : \frac{1}{2}

x = \frac{- 18 - 50}{2 \cdot 32} : - \frac{17}{16}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{17}{16}

6 x^{2} = 3 x + 7

2 x^{2} + 5 = 2 x

a, a^{2} + b^{2} + c^{2} = 1

y, 2 x y + x^{3} - 3 y^{2} = 5

y^{2} + 10 y + 24 = 0

What are the solutions to the equation 32x^2=17-18x ?
The solutions to the equation 32x^2=17-18x are x= 1/2 ,x=-17/16
Find the zeros of 32x^2=17-18x
The zeros of 32x^2=17-18x are x= 1/2 ,x=-17/16