What are the solutions to the equation -3x^2+6x=4 ?

The solutions to the equation -3x^2+6x=4 are x=1-i(sqrt(3))/3 ,x=1+i(sqrt(3))/3

Find the zeros of -3x^2+6x=4

The zeros of -3x^2+6x=4 are x=1-i(sqrt(3))/3 ,x=1+i(sqrt(3))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 x^{2} + 6 x = 4

x = 1 - i \frac{3}{3}, x = 1 + i \frac{3}{3}

Solution steps

- 3 x^{2} + 6 x = 4

Move

4

to the left side

- 3 x^{2} + 6 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) ( - 4 )}{2 ( - 3 )}

Simplify

6^{2} - 4 (- 3) (- 4) : 23 i

x_{1, 2} = \frac{- 6 \pm 2 3 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 3 i}{2 ( - 3 )}, x_{2} = \frac{- 6 - 2 3 i}{2 ( - 3 )}

x = \frac{- 6 + 2 3 i}{2 ( - 3 )} : 1 - i \frac{3}{3}

x = \frac{- 6 - 2 3 i}{2 ( - 3 )} : 1 + i \frac{3}{3}

The solutions to the quadratic equation are:

x = 1 - i \frac{3}{3}, x = 1 + i \frac{3}{3}

7 n^{2} - 19 = 5 n

(x + 7) (x + 5) = 3

6 x^{2} - 7 x - 3 = 0

x (x - 6) = - 3

x^{2} - 4 x + 2 = 0

What are the solutions to the equation -3x^2+6x=4 ?
The solutions to the equation -3x^2+6x=4 are x=1-i(sqrt(3))/3 ,x=1+i(sqrt(3))/3
Find the zeros of -3x^2+6x=4
The zeros of -3x^2+6x=4 are x=1-i(sqrt(3))/3 ,x=1+i(sqrt(3))/3