What are the solutions to the equation completesquare x^2-4x+2=0 ?

The solutions to the equation completesquare x^2-4x+2=0 are x=sqrt(2)+2,x=-sqrt(2)+2

Find the zeros of completesquare x^2-4x+2=0

The zeros of completesquare x^2-4x+2=0 are x=sqrt(2)+2,x=-sqrt(2)+2

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x^{2} - 4 x + 2 = 0

x = 2 + 2, x = - 2 + 2

Decimal Notation

x = 3.41421 \dots, x = 0.58578 \dots

Solution steps

x^{2} - 4 x + 2 = 0

Move

2

to the right side

x^{2} - 4 x = - 2

Rewrite in the form

(x + a)^{2} = b

(x - 2)^{2} = 2

For

the solutions are

f (x) = a, - a

Solve

x - 2 = 2 : x = 2 + 2

Solve

x - 2 = - 2 : x = - 2 + 2

The solutions to the quadratic equation are:

x = 2 + 2, x = - 2 + 2

x^{2} - 8 x + 15 = 0

n^{2} + 6 n - 27 = 0

x^{2} - 4 x + 4 = 0

- 5 x^{2} + 9 x + 2 = 0

(x^{2} + 2 x + 1) = 0

What are the solutions to the equation completesquare x^2-4x+2=0 ?
The solutions to the equation completesquare x^2-4x+2=0 are x=sqrt(2)+2,x=-sqrt(2)+2
Find the zeros of completesquare x^2-4x+2=0
The zeros of completesquare x^2-4x+2=0 are x=sqrt(2)+2,x=-sqrt(2)+2