What are the solutions to the equation 12x^2+15x=0 ?

The solutions to the equation 12x^2+15x=0 are x=0,x=-5/4

Find the zeros of 12x^2+15x=0

The zeros of 12x^2+15x=0 are x=0,x=-5/4

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12 x^{2} + 15 x = 0

x = 0, x = - \frac{5}{4}

Decimal Notation

x = 0, x = - 1.25

Solution steps

12 x^{2} + 15 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 12 \cdot 0}{2 \cdot 12}

1 5^{2} - 4 \cdot 12 \cdot 0 = 15

x_{1, 2} = \frac{- 15 \pm 15}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 15 + 15}{2 \cdot 12}, x_{2} = \frac{- 15 - 15}{2 \cdot 12}

x = \frac{- 15 + 15}{2 \cdot 12} : 0

x = \frac{- 15 - 15}{2 \cdot 12} : - \frac{5}{4}

The solutions to the quadratic equation are:

x = 0, x = - \frac{5}{4}

(a + 1) x^{2} + (2 a + 1) x - a = 30

x, x^{2} + x - 1 = 0

1.77 \cdot 1 0^{- 6} - 1.77 \cdot 1 0^{- 5} x - x^{2} = 0

\frac{1}{5} (x + 3)^{2} - 2 = 18

32 x^{2} - 16 x = 0

What are the solutions to the equation 12x^2+15x=0 ?
The solutions to the equation 12x^2+15x=0 are x=0,x=-5/4
Find the zeros of 12x^2+15x=0
The zeros of 12x^2+15x=0 are x=0,x=-5/4