What are the solutions to the equation 1/5 (x+3)^2-2=18 ?

The solutions to the equation 1/5 (x+3)^2-2=18 are x=7,x=-13

Find the zeros of 1/5 (x+3)^2-2=18

The zeros of 1/5 (x+3)^2-2=18 are x=7,x=-13

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\frac{1}{5} (x + 3)^{2} - 2 = 18

x = 7, x = - 13

Solution steps

\frac{1}{5} (x + 3)^{2} - 2 = 18

Move

2

to the right side

\frac{1}{5} (x + 3)^{2} = 20

Multiply both sides by

5

(x + 3)^{2} = 100

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 100 : x = 7

Solve

x + 3 = - 100 : x = - 13

The solutions to the quadratic equation are:

x = 7, x = - 13

32 x^{2} - 16 x = 0

4 x^{2} - x = 3

x^{2} + x^{2} = 2^{4}

4 x^{2} - 14 x + 12 = 0

x + 18 + 2 x^{2} = - 5 x + 3

What are the solutions to the equation 1/5 (x+3)^2-2=18 ?
The solutions to the equation 1/5 (x+3)^2-2=18 are x=7,x=-13
Find the zeros of 1/5 (x+3)^2-2=18
The zeros of 1/5 (x+3)^2-2=18 are x=7,x=-13