What are the solutions to the equation x^2+x^2=2^4 ?

The solutions to the equation x^2+x^2=2^4 are x=2sqrt(2),x=-2sqrt(2)

Find the zeros of x^2+x^2=2^4

The zeros of x^2+x^2=2^4 are x=2sqrt(2),x=-2sqrt(2)

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x^{2} + x^{2} = 2^{4}

x = 22, x = - 22

Decimal Notation

x = 2.82842 \dots, x = - 2.82842 \dots

Solution steps

x^{2} + x^{2} = 2^{4}

Add similar elements:

x^{2} + x^{2} = 2 x^{2}

2 x^{2} = 2^{4}

2^{4} = 16

2 x^{2} = 16

Divide both sides by

2

x^{2} = 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 8, x = - 8

8 = 22

- 8 = - 22

x = 22, x = - 22

4 x^{2} - 14 x + 12 = 0

x + 18 + 2 x^{2} = - 5 x + 3

x^{2} - 9 x - 4 = 0

x^{2} - 4 x - 12

2 (x + 3)^{2} + 1 = 9

What are the solutions to the equation x^2+x^2=2^4 ?
The solutions to the equation x^2+x^2=2^4 are x=2sqrt(2),x=-2sqrt(2)
Find the zeros of x^2+x^2=2^4
The zeros of x^2+x^2=2^4 are x=2sqrt(2),x=-2sqrt(2)