What are the solutions to the equation 2x^2+8=26 ?

The solutions to the equation 2x^2+8=26 are x=3,x=-3

Find the zeros of 2x^2+8=26

The zeros of 2x^2+8=26 are x=3,x=-3

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2 x^{2} + 8 = 26

x = 3, x = - 3

Solution steps

2 x^{2} + 8 = 26

Move

8

to the right side

2 x^{2} = 18

Divide both sides by

2

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

x^{2} - 4 x - 1 = 0

x^{2} + 10 x - 8 = 0

- \frac{7}{2} x^{2} + 3 x + \frac{8}{3}

(x + 1)^{2} + 2 x = 3 x (x + 1) + 5

(x - 3)^{2} + (x - 1)^{2} = 0

What are the solutions to the equation 2x^2+8=26 ?
The solutions to the equation 2x^2+8=26 are x=3,x=-3
Find the zeros of 2x^2+8=26
The zeros of 2x^2+8=26 are x=3,x=-3