What are the solutions to the equation 16x^2+64x+65=0 ?

The solutions to the equation 16x^2+64x+65=0 are x=-2+i 1/4 ,x=-2-i 1/4

Find the zeros of 16x^2+64x+65=0

The zeros of 16x^2+64x+65=0 are x=-2+i 1/4 ,x=-2-i 1/4

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16 x^{2} + 64 x + 65 = 0

x = - 2 + i \frac{1}{4}, x = - 2 - i \frac{1}{4}

Solution steps

16 x^{2} + 64 x + 65 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 64 \pm 6 4 ^{2} - 4 \cdot 16 \cdot 65}{2 \cdot 16}

Simplify

6 4^{2} - 4 \cdot 16 \cdot 65 : 8 i

x_{1, 2} = \frac{- 64 \pm 8 i}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- 64 + 8 i}{2 \cdot 16}, x_{2} = \frac{- 64 - 8 i}{2 \cdot 16}

x = \frac{- 64 + 8 i}{2 \cdot 16} : - 2 + i \frac{1}{4}

x = \frac{- 64 - 8 i}{2 \cdot 16} : - 2 - i \frac{1}{4}

The solutions to the quadratic equation are:

x = - 2 + i \frac{1}{4}, x = - 2 - i \frac{1}{4}

4 x^{2} - 31 = 49

9 s^{2} + 6 s + 1 = 0

(x - 5)^{2} + 81 = 0

x, z = 9 - x^{2} - y^{2}

k, \frac{d k}{d t} = 3 e^{2 t} k^{2} - 5 k

What are the solutions to the equation 16x^2+64x+65=0 ?
The solutions to the equation 16x^2+64x+65=0 are x=-2+i 1/4 ,x=-2-i 1/4
Find the zeros of 16x^2+64x+65=0
The zeros of 16x^2+64x+65=0 are x=-2+i 1/4 ,x=-2-i 1/4