What are the solutions to the equation 9s^2+6s+1=0 ?

The solutions to the equation 9s^2+6s+1=0 are s=-1/3

Find the zeros of 9s^2+6s+1=0

The zeros of 9s^2+6s+1=0 are s=-1/3

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9 s^{2} + 6 s + 1 = 0

s = - \frac{1}{3}

Decimal Notation

s = - 0.33333 \dots

Solution steps

9 s^{2} + 6 s + 1 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

6^{2} - 4 \cdot 9 \cdot 1 = 0

s_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 9}

s = \frac{- 6}{2 \cdot 9}

\frac{- 6}{2 \cdot 9} = - \frac{1}{3}

s = - \frac{1}{3}

The solution to the quadratic equation is:

s = - \frac{1}{3}

(x - 5)^{2} + 81 = 0

x, z = 9 - x^{2} - y^{2}

k, \frac{d k}{d t} = 3 e^{2 t} k^{2} - 5 k

3 x^{2} - 12 x - 135 = 0

2 x^{2} + 10 x + 6 = 0

What are the solutions to the equation 9s^2+6s+1=0 ?
The solutions to the equation 9s^2+6s+1=0 are s=-1/3
Find the zeros of 9s^2+6s+1=0
The zeros of 9s^2+6s+1=0 are s=-1/3