What are the solutions to the equation 2x^2+10x+6=0 ?

The solutions to the equation 2x^2+10x+6=0 are x=(-5+sqrt(13))/2 ,x=-(5+sqrt(13))/2

Find the zeros of 2x^2+10x+6=0

The zeros of 2x^2+10x+6=0 are x=(-5+sqrt(13))/2 ,x=-(5+sqrt(13))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 10 x + 6 = 0

x = \frac{- 5 + 13}{2}, x = - \frac{5 + 13}{2}

Decimal Notation

x = - 0.69722 \dots, x = - 4.30277 \dots

Solution steps

2 x^{2} + 10 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 \cdot 6 = 213

x_{1, 2} = \frac{- 10 \pm 2 13}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 10 + 2 13}{2 \cdot 2}, x_{2} = \frac{- 10 - 2 13}{2 \cdot 2}

x = \frac{- 10 + 2 13}{2 \cdot 2} : \frac{- 5 + 13}{2}

x = \frac{- 10 - 2 13}{2 \cdot 2} : - \frac{5 + 13}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 13}{2}, x = - \frac{5 + 13}{2}

6 x^{2} - 60 x + 126 = 0

7 x^{2} + 4 x - 1 = 0

x, x^{2} + y^{2} + z^{2} = 8

x, x^{2} + y^{2} + z^{2} = 6

(x - 4)^{2} + 8 = 0

What are the solutions to the equation 2x^2+10x+6=0 ?
The solutions to the equation 2x^2+10x+6=0 are x=(-5+sqrt(13))/2 ,x=-(5+sqrt(13))/2
Find the zeros of 2x^2+10x+6=0
The zeros of 2x^2+10x+6=0 are x=(-5+sqrt(13))/2 ,x=-(5+sqrt(13))/2