What are the solutions to the equation x^2+5x+15=11 ?

The solutions to the equation x^2+5x+15=11 are x=-1,x=-4

Find the zeros of x^2+5x+15=11

The zeros of x^2+5x+15=11 are x=-1,x=-4

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x^{2} + 5 x + 15 = 11

x = - 1, x = - 4

Solution steps

x^{2} + 5 x + 15 = 11

Move

11

to the left side

x^{2} + 5 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 4 = 3

x_{1, 2} = \frac{- 5 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 3}{2 \cdot 1}, x_{2} = \frac{- 5 - 3}{2 \cdot 1}

x = \frac{- 5 + 3}{2 \cdot 1} : - 1

x = \frac{- 5 - 3}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = - 1, x = - 4

x^{2} - 8 x = - 3

6 x^{2} + 11 b x = 10 b^{2}

t^{2} - t = 0

x^{2} - 12 x - 40 = 0

x, x^{2} - 4 x y + y^{2} = 0

What are the solutions to the equation x^2+5x+15=11 ?
The solutions to the equation x^2+5x+15=11 are x=-1,x=-4
Find the zeros of x^2+5x+15=11
The zeros of x^2+5x+15=11 are x=-1,x=-4