What are the solutions to the equation (3q-8)^2=-4 ?

The solutions to the equation (3q-8)^2=-4 are q= 8/3+i 2/3 ,q= 8/3-i 2/3

Find the zeros of (3q-8)^2=-4

The zeros of (3q-8)^2=-4 are q= 8/3+i 2/3 ,q= 8/3-i 2/3

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(3 q - 8)^{2} = - 4

q = \frac{8}{3} + i \frac{2}{3}, q = \frac{8}{3} - i \frac{2}{3}

Solution steps

(3 q - 8)^{2} = - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 q - 8 = - 4 : q = \frac{8}{3} + i \frac{2}{3}

Solve

3 q - 8 = - - 4 : q = \frac{8}{3} - i \frac{2}{3}

The solutions to the quadratic equation are:

q = \frac{8}{3} + i \frac{2}{3}, q = \frac{8}{3} - i \frac{2}{3}

4 x^{2} + 2 x - 42 = 0

(x + 4) (2 x - 7) = 0

16 x^{2} - 24 x + 13 = 4

8 x^{2} + 63 = - 46 x

6 x^{2} - 6 x + 3 = 0

What are the solutions to the equation (3q-8)^2=-4 ?
The solutions to the equation (3q-8)^2=-4 are q= 8/3+i 2/3 ,q= 8/3-i 2/3
Find the zeros of (3q-8)^2=-4
The zeros of (3q-8)^2=-4 are q= 8/3+i 2/3 ,q= 8/3-i 2/3