What are the solutions to the equation X^2-5X+1=0 ?

The solutions to the equation X^2-5X+1=0 are X=(5+sqrt(21))/2 ,X=(5-sqrt(21))/2

Find the zeros of X^2-5X+1=0

The zeros of X^2-5X+1=0 are X=(5+sqrt(21))/2 ,X=(5-sqrt(21))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

X^{2} - 5 X + 1 = 0

X = \frac{5 + 21}{2}, X = \frac{5 - 21}{2}

Decimal Notation

X = 4.79128 \dots, X = 0.20871 \dots

Solution steps

X^{2} - 5 X + 1 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 1 = 21

X_{1, 2} = \frac{- ( - 5 ) \pm 21}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- ( - 5 ) + 21}{2 \cdot 1}, X_{2} = \frac{- ( - 5 ) - 21}{2 \cdot 1}

X = \frac{- ( - 5 ) + 21}{2 \cdot 1} : \frac{5 + 21}{2}

X = \frac{- ( - 5 ) - 21}{2 \cdot 1} : \frac{5 - 21}{2}

The solutions to the quadratic equation are:

X = \frac{5 + 21}{2}, X = \frac{5 - 21}{2}

(x + 1) (x + 4) = 8

x^{2} + 40 = 0

x^{2} + 490 = 0

x^{2} = 7 x + 4

8 x^{2} - 4 = 0

What are the solutions to the equation X^2-5X+1=0 ?
The solutions to the equation X^2-5X+1=0 are X=(5+sqrt(21))/2 ,X=(5-sqrt(21))/2
Find the zeros of X^2-5X+1=0
The zeros of X^2-5X+1=0 are X=(5+sqrt(21))/2 ,X=(5-sqrt(21))/2