What are the solutions to the equation x^2+40=0 ?

The solutions to the equation x^2+40=0 are x=2sqrt(10)i,x=-2sqrt(10)i

Find the zeros of x^2+40=0

The zeros of x^2+40=0 are x=2sqrt(10)i,x=-2sqrt(10)i

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x^{2} + 40 = 0

x = 210 i, x = - 210 i

Solution steps

x^{2} + 40 = 0

Move

40

to the right side

x^{2} = - 40

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 40, x = - - 40

- 40 = 210 i

- - 40 = - 210 i

x = 210 i, x = - 210 i

x^{2} + 490 = 0

x^{2} = 7 x + 4

8 x^{2} - 4 = 0

x^{2} + 12 x = 64

64 - x^{2} = 0

What are the solutions to the equation x^2+40=0 ?
The solutions to the equation x^2+40=0 are x=2sqrt(10)i,x=-2sqrt(10)i
Find the zeros of x^2+40=0
The zeros of x^2+40=0 are x=2sqrt(10)i,x=-2sqrt(10)i