What are the solutions to the equation -5x^2+6x+14=-5 ?

The solutions to the equation -5x^2+6x+14=-5 are x=-(-3+2sqrt(26))/5 ,x=(3+2sqrt(26))/5

Find the zeros of -5x^2+6x+14=-5

The zeros of -5x^2+6x+14=-5 are x=-(-3+2sqrt(26))/5 ,x=(3+2sqrt(26))/5

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- 5 x^{2} + 6 x + 14 = - 5

x = - \frac{- 3 + 2 26}{5}, x = \frac{3 + 2 26}{5}

Decimal Notation

x = - 1.43960 \dots, x = 2.63960 \dots

Solution steps

- 5 x^{2} + 6 x + 14 = - 5

Move

5

to the left side

- 5 x^{2} + 6 x + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 5 ) \cdot 19}{2 ( - 5 )}

6^{2} - 4 (- 5) \cdot 19 = 426

x_{1, 2} = \frac{- 6 \pm 4 26}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 6 + 4 26}{2 ( - 5 )}, x_{2} = \frac{- 6 - 4 26}{2 ( - 5 )}

x = \frac{- 6 + 4 26}{2 ( - 5 )} : - \frac{- 3 + 2 26}{5}

x = \frac{- 6 - 4 26}{2 ( - 5 )} : \frac{3 + 2 26}{5}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 2 26}{5}, x = \frac{3 + 2 26}{5}

5 x^{2} + 6 x + 9 = 0

(x + 4)^{2} = 28

(x + 4)^{2} = 20

5 x^{2} + 6 x + 4 = 0

27 x^{2} - 27 = 0

What are the solutions to the equation -5x^2+6x+14=-5 ?
The solutions to the equation -5x^2+6x+14=-5 are x=-(-3+2sqrt(26))/5 ,x=(3+2sqrt(26))/5
Find the zeros of -5x^2+6x+14=-5
The zeros of -5x^2+6x+14=-5 are x=-(-3+2sqrt(26))/5 ,x=(3+2sqrt(26))/5