What are the solutions to the equation 0=-x^2-12x+17 ?

The solutions to the equation 0=-x^2-12x+17 are x=-6-sqrt(53),x=sqrt(53)-6

Find the zeros of 0=-x^2-12x+17

The zeros of 0=-x^2-12x+17 are x=-6-sqrt(53),x=sqrt(53)-6

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0 = - x^{2} - 12 x + 17

x = - 6 - 53, x = 53 - 6

Decimal Notation

x = - 13.28010 \dots, x = 1.28010 \dots

Solution steps

0 = - x^{2} - 12 x + 17

Switch sides

- x^{2} - 12 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 ( - 1 ) \cdot 17}{2 ( - 1 )}

(- 12)^{2} - 4 (- 1) \cdot 17 = 253

x_{1, 2} = \frac{- ( - 12 ) \pm 2 53}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 53}{2 ( - 1 )}, x_{2} = \frac{- ( - 12 ) - 2 53}{2 ( - 1 )}

x = \frac{- ( - 12 ) + 2 53}{2 ( - 1 )} : - 6 - 53

x = \frac{- ( - 12 ) - 2 53}{2 ( - 1 )} : 53 - 6

The solutions to the quadratic equation are:

x = - 6 - 53, x = 53 - 6

4 = x^{2} - 4 x + 4

x, x^{2} - 2 y^{2} = 0

x^{2} - 6 x - 7 = 0

x^{2} + 7 = 16

- 2 y + 5 + y^{2} = - 6 y + 2 y^{2}

What are the solutions to the equation 0=-x^2-12x+17 ?
The solutions to the equation 0=-x^2-12x+17 are x=-6-sqrt(53),x=sqrt(53)-6
Find the zeros of 0=-x^2-12x+17
The zeros of 0=-x^2-12x+17 are x=-6-sqrt(53),x=sqrt(53)-6