What are the solutions to the equation 3x^2-24x+21=0 ?

The solutions to the equation 3x^2-24x+21=0 are x=7,x=1

Find the zeros of 3x^2-24x+21=0

The zeros of 3x^2-24x+21=0 are x=7,x=1

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3 x^{2} - 24 x + 21 = 0

x = 7, x = 1

Solution steps

3 x^{2} - 24 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 3 \cdot 21}{2 \cdot 3}

(- 24)^{2} - 4 \cdot 3 \cdot 21 = 18

x_{1, 2} = \frac{- ( - 24 ) \pm 18}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 18}{2 \cdot 3}, x_{2} = \frac{- ( - 24 ) - 18}{2 \cdot 3}

x = \frac{- ( - 24 ) + 18}{2 \cdot 3} : 7

x = \frac{- ( - 24 ) - 18}{2 \cdot 3} : 1

The solutions to the quadratic equation are:

x = 7, x = 1

2 x^{2} - 6 x + 11 = 0

x^{2} + 4 x + 30 = 0

- 4 x^{2} + 4 x - 3 = 0

20 x - 9 = x^{2}

2 x^{2} - 14 x - 16 = 0

What are the solutions to the equation 3x^2-24x+21=0 ?
The solutions to the equation 3x^2-24x+21=0 are x=7,x=1
Find the zeros of 3x^2-24x+21=0
The zeros of 3x^2-24x+21=0 are x=7,x=1