What are the solutions to the equation y^2+8y+11=0 ?

The solutions to the equation y^2+8y+11=0 are y=-4+sqrt(5),y=-4-sqrt(5)

Find the zeros of y^2+8y+11=0

The zeros of y^2+8y+11=0 are y=-4+sqrt(5),y=-4-sqrt(5)

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y^{2} + 8 y + 11 = 0

y = - 4 + 5, y = - 4 - 5

Decimal Notation

y = - 1.76393 \dots, y = - 6.23606 \dots

Solution steps

y^{2} + 8 y + 11 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 11}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 11 = 25

y_{1, 2} = \frac{- 8 \pm 2 5}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 8 + 2 5}{2 \cdot 1}, y_{2} = \frac{- 8 - 2 5}{2 \cdot 1}

y = \frac{- 8 + 2 5}{2 \cdot 1} : - 4 + 5

y = \frac{- 8 - 2 5}{2 \cdot 1} : - 4 - 5

The solutions to the quadratic equation are:

y = - 4 + 5, y = - 4 - 5

14 - 5 x - x^{2} = 0

3^{2} + y^{2} = 5^{2}

x^{2} + 6 x = 3

2 x^{2} + 9 x + 14 = 0

6 x^{2} - 13 x + 6 = 0

What are the solutions to the equation y^2+8y+11=0 ?
The solutions to the equation y^2+8y+11=0 are y=-4+sqrt(5),y=-4-sqrt(5)
Find the zeros of y^2+8y+11=0
The zeros of y^2+8y+11=0 are y=-4+sqrt(5),y=-4-sqrt(5)