What are the solutions to the equation 2x^2+9x+14=0 ?

The solutions to the equation 2x^2+9x+14=0 are x=-9/4+i(sqrt(31))/4 ,x=-9/4-i(sqrt(31))/4

Find the zeros of 2x^2+9x+14=0

The zeros of 2x^2+9x+14=0 are x=-9/4+i(sqrt(31))/4 ,x=-9/4-i(sqrt(31))/4

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2 x^{2} + 9 x + 14 = 0

x = - \frac{9}{4} + i \frac{31}{4}, x = - \frac{9}{4} - i \frac{31}{4}

Solution steps

2 x^{2} + 9 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 \cdot 14}{2 \cdot 2}

Simplify

9^{2} - 4 \cdot 2 \cdot 14 : 31 i

x_{1, 2} = \frac{- 9 \pm 31 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 9 + 31 i}{2 \cdot 2}, x_{2} = \frac{- 9 - 31 i}{2 \cdot 2}

x = \frac{- 9 + 31 i}{2 \cdot 2} : - \frac{9}{4} + i \frac{31}{4}

x = \frac{- 9 - 31 i}{2 \cdot 2} : - \frac{9}{4} - i \frac{31}{4}

The solutions to the quadratic equation are:

x = - \frac{9}{4} + i \frac{31}{4}, x = - \frac{9}{4} - i \frac{31}{4}

6 x^{2} - 13 x + 6 = 0

y^{2} - 11 y = - 6

12 x^{2} + 11 x - 15 = 0

p^{2} - 4 p = 1

x, w = x^{2} + y^{2} + z^{2}

What are the solutions to the equation 2x^2+9x+14=0 ?
The solutions to the equation 2x^2+9x+14=0 are x=-9/4+i(sqrt(31))/4 ,x=-9/4-i(sqrt(31))/4
Find the zeros of 2x^2+9x+14=0
The zeros of 2x^2+9x+14=0 are x=-9/4+i(sqrt(31))/4 ,x=-9/4-i(sqrt(31))/4