What are the solutions to the equation y^2-11y=-6 ?

The solutions to the equation y^2-11y=-6 are y=(11+sqrt(97))/2 ,y=(11-sqrt(97))/2

Find the zeros of y^2-11y=-6

The zeros of y^2-11y=-6 are y=(11+sqrt(97))/2 ,y=(11-sqrt(97))/2

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y^{2} - 11 y = - 6

y = \frac{11 + 97}{2}, y = \frac{11 - 97}{2}

Decimal Notation

y = 10.42442 \dots, y = 0.57557 \dots

Solution steps

y^{2} - 11 y = - 6

Move

6

to the left side

y^{2} - 11 y + 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 6 = 97

y_{1, 2} = \frac{- ( - 11 ) \pm 97}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 11 ) + 97}{2 \cdot 1}, y_{2} = \frac{- ( - 11 ) - 97}{2 \cdot 1}

y = \frac{- ( - 11 ) + 97}{2 \cdot 1} : \frac{11 + 97}{2}

y = \frac{- ( - 11 ) - 97}{2 \cdot 1} : \frac{11 - 97}{2}

The solutions to the quadratic equation are:

y = \frac{11 + 97}{2}, y = \frac{11 - 97}{2}

12 x^{2} + 11 x - 15 = 0

p^{2} - 4 p = 1

x, w = x^{2} + y^{2} + z^{2}

- 4 r^{2} - 4 r = 6

36 x^{2} + 84 x + 49 = 0

What are the solutions to the equation y^2-11y=-6 ?
The solutions to the equation y^2-11y=-6 are y=(11+sqrt(97))/2 ,y=(11-sqrt(97))/2
Find the zeros of y^2-11y=-6
The zeros of y^2-11y=-6 are y=(11+sqrt(97))/2 ,y=(11-sqrt(97))/2