What are the solutions to the equation -4r^2-4r=6 ?

The solutions to the equation -4r^2-4r=6 are r=-1/2-i(sqrt(5))/2 ,r=-1/2+i(sqrt(5))/2

Find the zeros of -4r^2-4r=6

The zeros of -4r^2-4r=6 are r=-1/2-i(sqrt(5))/2 ,r=-1/2+i(sqrt(5))/2

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- 4 r^{2} - 4 r = 6

r = - \frac{1}{2} - i \frac{5}{2}, r = - \frac{1}{2} + i \frac{5}{2}

Solution steps

- 4 r^{2} - 4 r = 6

Move

6

to the left side

- 4 r^{2} - 4 r - 6 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 4 ) ( - 6 )}{2 ( - 4 )}

Simplify

(- 4)^{2} - 4 (- 4) (- 6) : 45 i

r_{1, 2} = \frac{- ( - 4 ) \pm 4 5 i}{2 ( - 4 )}

Separate the solutions

r_{1} = \frac{- ( - 4 ) + 4 5 i}{2 ( - 4 )}, r_{2} = \frac{- ( - 4 ) - 4 5 i}{2 ( - 4 )}

r = \frac{- ( - 4 ) + 4 5 i}{2 ( - 4 )} : - \frac{1}{2} - i \frac{5}{2}

r = \frac{- ( - 4 ) - 4 5 i}{2 ( - 4 )} : - \frac{1}{2} + i \frac{5}{2}

The solutions to the quadratic equation are:

r = - \frac{1}{2} - i \frac{5}{2}, r = - \frac{1}{2} + i \frac{5}{2}

36 x^{2} + 84 x + 49 = 0

x^{2} = 1 0^{2} + 6^{2}

x^{2} - 2 x - 5

(x + 8)^{2} = - 4

x^{2} - 2 x = 0

What are the solutions to the equation -4r^2-4r=6 ?
The solutions to the equation -4r^2-4r=6 are r=-1/2-i(sqrt(5))/2 ,r=-1/2+i(sqrt(5))/2
Find the zeros of -4r^2-4r=6
The zeros of -4r^2-4r=6 are r=-1/2-i(sqrt(5))/2 ,r=-1/2+i(sqrt(5))/2