What is the answer to solvefor f,f=f(x+2)-3 ?

The answer to solvefor f,f=f(x+2)-3 is f= 3/(x+1);\quad x\ne-1

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solvefor f,f=f(x+2)-3

solve for

f, f = f (x + 2) - 3

f = \frac{3}{x + 1}; x \neq = - 1

Solution steps

f = f (x + 2) - 3

Expand

f (x + 2) : x f + 2 f

f = x f + 2 f - 3

Subtract

x f + 2 f

from both sides

f - (x f + 2 f) = x f + 2 f - 3 - (x f + 2 f)

Simplify

- x f - f = - 3

Factor

- x f - f : - f (x + 1)

- f (x + 1) = - 3

Divide both sides by

- (x + 1); x \neq = - 1

f = \frac{3}{x + 1}; x \neq = - 1

x^{2} + 9 = 8 x

x, x^{2} y + y^{2} x = 6

p, x^{2} p^{2} + x y p - 6 y^{2} = 0

x^{2} - 9 x + 16 = 0

(2 - k) x^{2} + 2 k x - k + 2 = 0

What is the answer to solvefor f,f=f(x+2)-3 ?
The answer to solvefor f,f=f(x+2)-3 is f= 3/(x+1);\quad x\ne-1