What are the solutions to the equation solvefor p,x^2p^2+xyp-6y^2=0 ?

The solutions to the equation solvefor p,x^2p^2+xyp-6y^2=0 are p=(2y)/x ,p=-(3y)/x ;\quad x\ne 0

Find the zeros of solvefor p,x^2p^2+xyp-6y^2=0

The zeros of solvefor p,x^2p^2+xyp-6y^2=0 are p=(2y)/x ,p=-(3y)/x ;\quad x\ne 0

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solve for

p, x^{2} p^{2} + x y p - 6 y^{2} = 0

p = \frac{2 y}{x}, p = - \frac{3 y}{x}; x \neq = 0

Solution steps

x^{2} p^{2} + x y p - 6 y^{2} = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- x y \pm ( x y ) ^{2} - 4 x ^{2} ( - 6 y ^{2} )}{2 x ^{2}}

Simplify

(x y)^{2} - 4 x^{2} (- 6 y^{2}) : 5 x y

p_{1, 2} = \frac{- x y \pm 5 x y}{2 x ^{2}}; x \neq = 0

Separate the solutions

p_{1} = \frac{- x y + 5 x y}{2 x ^{2}}, p_{2} = \frac{- x y - 5 x y}{2 x ^{2}}

p = \frac{- x y + 5 x y}{2 x ^{2}} : \frac{2 y}{x}

p = \frac{- x y - 5 x y}{2 x ^{2}} : - \frac{3 y}{x}

The solutions to the quadratic equation are:

p = \frac{2 y}{x}, p = - \frac{3 y}{x}; x \neq = 0

x^{2} - 9 x + 16 = 0

(2 - k) x^{2} + 2 k x - k + 2 = 0

x^{2} - 7 x - 10 = 8

x^{2} - 9 x + 13 = 0

x^{2} - 2 x - 5 = 0

What are the solutions to the equation solvefor p,x^2p^2+xyp-6y^2=0 ?
The solutions to the equation solvefor p,x^2p^2+xyp-6y^2=0 are p=(2y)/x ,p=-(3y)/x ;\quad x\ne 0
Find the zeros of solvefor p,x^2p^2+xyp-6y^2=0
The zeros of solvefor p,x^2p^2+xyp-6y^2=0 are p=(2y)/x ,p=-(3y)/x ;\quad x\ne 0