What are the solutions to the equation -2x^2+6x+5=0 ?

The solutions to the equation -2x^2+6x+5=0 are x=-(-3+sqrt(19))/2 ,x=(3+sqrt(19))/2

Find the zeros of -2x^2+6x+5=0

The zeros of -2x^2+6x+5=0 are x=-(-3+sqrt(19))/2 ,x=(3+sqrt(19))/2

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- 2 x^{2} + 6 x + 5 = 0

x = - \frac{- 3 + 19}{2}, x = \frac{3 + 19}{2}

Decimal Notation

x = - 0.67944 \dots, x = 3.67944 \dots

Solution steps

- 2 x^{2} + 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 2 ) \cdot 5}{2 ( - 2 )}

6^{2} - 4 (- 2) \cdot 5 = 219

x_{1, 2} = \frac{- 6 \pm 2 19}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 19}{2 ( - 2 )}, x_{2} = \frac{- 6 - 2 19}{2 ( - 2 )}

x = \frac{- 6 + 2 19}{2 ( - 2 )} : - \frac{- 3 + 19}{2}

x = \frac{- 6 - 2 19}{2 ( - 2 )} : \frac{3 + 19}{2}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 19}{2}, x = \frac{3 + 19}{2}

1 + 4 + 7 + (3 n - 2) = \frac{n ( 3 n - 1 )}{2}

x, x^{2} - k x + 121 = 0

n^{2} + n = 0

20 x^{2} + 40 x = 0

x^{2} - 12 x + 35 = 195

What are the solutions to the equation -2x^2+6x+5=0 ?
The solutions to the equation -2x^2+6x+5=0 are x=-(-3+sqrt(19))/2 ,x=(3+sqrt(19))/2
Find the zeros of -2x^2+6x+5=0
The zeros of -2x^2+6x+5=0 are x=-(-3+sqrt(19))/2 ,x=(3+sqrt(19))/2