What are the solutions to the equation 2x^2-7x-10=0 ?

The solutions to the equation 2x^2-7x-10=0 are x=(7+sqrt(129))/4 ,x=(7-sqrt(129))/4

Find the zeros of 2x^2-7x-10=0

The zeros of 2x^2-7x-10=0 are x=(7+sqrt(129))/4 ,x=(7-sqrt(129))/4

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2 x^{2} - 7 x - 10 = 0

x = \frac{7 + 129}{4}, x = \frac{7 - 129}{4}

Solution steps

2 x^{2} - 7 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 10) = 129

x_{1, 2} = \frac{- ( - 7 ) \pm 129}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 129}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 129}{2 \cdot 2}

x = \frac{- ( - 7 ) + 129}{2 \cdot 2} : \frac{7 + 129}{4}

x = \frac{- ( - 7 ) - 129}{2 \cdot 2} : \frac{7 - 129}{4}

The solutions to the quadratic equation are:

x = \frac{7 + 129}{4}, x = \frac{7 - 129}{4}

3 x^{2} + 11 x + 7 = 0

5 x^{2} - 90 x = - 370

(x + 1)^{2} = - 9

(x + 1)^{2} = - 4

(x + 1)^{2} = 30

What are the solutions to the equation 2x^2-7x-10=0 ?
The solutions to the equation 2x^2-7x-10=0 are x=(7+sqrt(129))/4 ,x=(7-sqrt(129))/4
Find the zeros of 2x^2-7x-10=0
The zeros of 2x^2-7x-10=0 are x=(7+sqrt(129))/4 ,x=(7-sqrt(129))/4