What are the solutions to the equation (k^2)/(1.2-7)=23 ?

The solutions to the equation (k^2)/(1.2-7)=23 are k=sqrt(667/5)i,k=-sqrt(667/5)i

Find the zeros of (k^2)/(1.2-7)=23

The zeros of (k^2)/(1.2-7)=23 are k=sqrt(667/5)i,k=-sqrt(667/5)i

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\frac{k ^{2}}{1.2 - 7} = 23

k = \frac{667}{5} i, k = - \frac{667}{5} i

Solution steps

\frac{k ^{2}}{1.2 - 7} = 23

Multiply both sides by

1.2 - 7

k^{2} = - 133.4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = - 133.4, k = - - 133.4

- 133.4 = \frac{667}{5} i

- - 133.4 = - \frac{667}{5} i

k = \frac{667}{5} i, k = - \frac{667}{5} i

x^{2} - 4 + 3 = 0

6 x^{2} - 2 x = 20

0 = x^{2} + 9

x^{2} + 3 x - 1 = x - 2 x^{2}

x^{2} - 2 x - 10 = 9

What are the solutions to the equation (k^2)/(1.2-7)=23 ?
The solutions to the equation (k^2)/(1.2-7)=23 are k=sqrt(667/5)i,k=-sqrt(667/5)i
Find the zeros of (k^2)/(1.2-7)=23
The zeros of (k^2)/(1.2-7)=23 are k=sqrt(667/5)i,k=-sqrt(667/5)i