What are the solutions to the equation x^2+3x-1=x-2x^2 ?

The solutions to the equation x^2+3x-1=x-2x^2 are x= 1/3 ,x=-1

Find the zeros of x^2+3x-1=x-2x^2

The zeros of x^2+3x-1=x-2x^2 are x= 1/3 ,x=-1

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x^{2} + 3 x - 1 = x - 2 x^{2}

x = \frac{1}{3}, x = - 1

Solution steps

x^{2} + 3 x - 1 = x - 2 x^{2}

Move

2 x^{2}

to the left side

3 x^{2} + 3 x - 1 = x

Move

x

to the left side

3 x^{2} + 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 1) = 4

x_{1, 2} = \frac{- 2 \pm 4}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 4}{2 \cdot 3}, x_{2} = \frac{- 2 - 4}{2 \cdot 3}

x = \frac{- 2 + 4}{2 \cdot 3} : \frac{1}{3}

x = \frac{- 2 - 4}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 1

x^{2} - 2 x - 10 = 9

(r^{2} + 4) = 0

9 z^{2} + 14 z = 8 z - 1

\frac{x}{2} + 2 x^{2} = - x (x - 1)

0 = - x^{2} + 4 x

What are the solutions to the equation x^2+3x-1=x-2x^2 ?
The solutions to the equation x^2+3x-1=x-2x^2 are x= 1/3 ,x=-1
Find the zeros of x^2+3x-1=x-2x^2
The zeros of x^2+3x-1=x-2x^2 are x= 1/3 ,x=-1