What are the solutions to the equation -3x^2-6x-5=0 ?

The solutions to the equation -3x^2-6x-5=0 are x=-1-isqrt(2/3),x=-1+isqrt(2/3)

Find the zeros of -3x^2-6x-5=0

The zeros of -3x^2-6x-5=0 are x=-1-isqrt(2/3),x=-1+isqrt(2/3)

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- 3 x^{2} - 6 x - 5 = 0

x = - 1 - i \frac{2}{3}, x = - 1 + i \frac{2}{3}

Solution steps

- 3 x^{2} - 6 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 3 ) ( - 5 )}{2 ( - 3 )}

Simplify

(- 6)^{2} - 4 (- 3) (- 5) : 26 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 6 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 6 i}{2 ( - 3 )}, x_{2} = \frac{- ( - 6 ) - 2 6 i}{2 ( - 3 )}

x = \frac{- ( - 6 ) + 2 6 i}{2 ( - 3 )} : - 1 - i \frac{2}{3}

x = \frac{- ( - 6 ) - 2 6 i}{2 ( - 3 )} : - 1 + i \frac{2}{3}

The solutions to the quadratic equation are:

x = - 1 - i \frac{2}{3}, x = - 1 + i \frac{2}{3}

5 x^{2} - 36 = 0

- 16 t^{2} + 16 t + 32 = 0

x^{2} + 4 x + 3 = 0

x, x^{2} - x + 2 = 0

x, x^{2} - x + 1 = 0

What are the solutions to the equation -3x^2-6x-5=0 ?
The solutions to the equation -3x^2-6x-5=0 are x=-1-isqrt(2/3),x=-1+isqrt(2/3)
Find the zeros of -3x^2-6x-5=0
The zeros of -3x^2-6x-5=0 are x=-1-isqrt(2/3),x=-1+isqrt(2/3)