What are the solutions to the equation 5x^2-36=0 ?

The solutions to the equation 5x^2-36=0 are x= 6/(sqrt(5)),x=-6/(sqrt(5))

Find the zeros of 5x^2-36=0

The zeros of 5x^2-36=0 are x= 6/(sqrt(5)),x=-6/(sqrt(5))

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5 x^{2} - 36 = 0

x = \frac{6}{5}, x = - \frac{6}{5}

Solution steps

5 x^{2} - 36 = 0

Move

36

to the right side

5 x^{2} = 36

Divide both sides by

5

x^{2} = \frac{36}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{36}{5}, x = - \frac{36}{5}

\frac{36}{5} = \frac{6}{5}

- \frac{36}{5} = - \frac{6}{5}

x = \frac{6}{5}, x = - \frac{6}{5}

- 16 t^{2} + 16 t + 32 = 0

x^{2} + 4 x + 3 = 0

x, x^{2} - x + 2 = 0

x, x^{2} - x + 1 = 0

x, x^{2} - 4 x + 2 = 0

What are the solutions to the equation 5x^2-36=0 ?
The solutions to the equation 5x^2-36=0 are x= 6/(sqrt(5)),x=-6/(sqrt(5))
Find the zeros of 5x^2-36=0
The zeros of 5x^2-36=0 are x= 6/(sqrt(5)),x=-6/(sqrt(5))